x^2+200x-1680000=0

Solution for x^2+200x-1680000=0 equation:

x^2+200x-1680000=0

a = 1; b = 200; c = -1680000;
Δ = b2-4ac
Δ = 2002-4·1·(-1680000)
Δ = 6760000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6760000}=2600$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-2600}{2*1}=\frac{-2800}{2}
=-1400
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+2600}{2*1}=\frac{2400}{2}
=1200
$